Answer to Maths Olympiad Post

In one of my earlier posts, I talked about the Maths Olympiad, a worldwide mathematics competition. I finished it off with an example Maths Olympiad problem from excellent.org. Here it is in its full glory.

If x and y are real numbers satisfying
            x2 + xy = 20 and y2 + xy = 30
what is the value of xy?

Today I’m back to answer this problem.


x² + xy = 20
y² + xy = 30
(x² + xy) + (y² + xy) = 50
(x² + xy) x (y² + xy) = 600
((x² + xy) x (y² + xy)) ÷ ((x² + xy) + (y² + xy)) = xy 
600 ÷ 50 = xy
             = 12

Yours in numbers, 
Lachlan

Comments

  1. ((x² + xy) + (y² + xy)) ÷ ((x² + xy) x (y² + xy)) = xy, that cannnot be if x and y are whole numbers.

    ReplyDelete
    Replies
    1. It is meant to be ((x² + xy) x (y² + xy)) ÷ ((x² + xy) + (y² + xy))=xy

      Delete
  2. Okay I understand this question now. It is a very good question! You should explain how the fifth step is equal to xy. It is very interesting.

    ReplyDelete

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