Answer to Maths Olympiad Post
In one of my earlier posts, I talked about the Maths Olympiad, a worldwide
mathematics competition. I finished it off with an example Maths Olympiad
problem from excellent.org. Here it is in its full glory.
If
x and y are real numbers satisfying
x2 + xy = 20 and y2
+ xy = 30
what
is the value of xy?
Today
I’m back to answer this problem.
x² + xy = 20
y² + xy = 30
(x² + xy) + (y² + xy) = 50
(x² + xy) x (y² + xy) = 600
((x² + xy) x (y² + xy)) ÷ ((x² + xy) + (y² + xy)) = xy ∴
600 ÷ 50 = xy
= 12
y² + xy = 30
(x² + xy) + (y² + xy) = 50
(x² + xy) x (y² + xy) = 600
((x² + xy) x (y² + xy)) ÷ ((x² + xy) + (y² + xy)) = xy ∴
600 ÷ 50 = xy
= 12
Yours in numbers,
Lachlan
((x² + xy) + (y² + xy)) ÷ ((x² + xy) x (y² + xy)) = xy, that cannnot be if x and y are whole numbers.
ReplyDeleteIt is meant to be ((x² + xy) x (y² + xy)) ÷ ((x² + xy) + (y² + xy))=xy
DeleteOkay I understand this question now. It is a very good question! You should explain how the fifth step is equal to xy. It is very interesting.
ReplyDeleteI will ask Lachlan to do that
Delete